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56=0.4x^2-36x
We move all terms to the left:
56-(0.4x^2-36x)=0
We get rid of parentheses
-0.4x^2+36x+56=0
a = -0.4; b = 36; c = +56;
Δ = b2-4ac
Δ = 362-4·(-0.4)·56
Δ = 1385.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-\sqrt{1385.6}}{2*-0.4}=\frac{-36-\sqrt{1385.6}}{-0.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+\sqrt{1385.6}}{2*-0.4}=\frac{-36+\sqrt{1385.6}}{-0.8} $
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